How do you make an 8-to-1 multiplexer?
How do you make an 8-to-1 multiplexer?
An 8-to-1 multiplexer consists of eight data inputs D0 through D7, three input select lines S0 through S2 and a single output line Y. Depending on the select lines combinations, multiplexer selects the inputs.
How many select lines are there in a 8-to-1 multiplexer?
3 selection lines
The 8×1 multiplexer has 3 selection lines, 4 inputs, and 1 output. The 2×1 multiplexer has only 1 selection line. For getting 16 data inputs, we need two 8 ×1 multiplexers. The 8×1 multiplexer produces one output.
How do I combine multiple multiplexers?
To achieve the first two MUX is connected in parallel and then the output of those two are feeded as input to the 3rd MUX as shown below. The control/select line of the first two MUX is connected together to form a single line (S0) and then the control line of the 3rd MUX is used as the second control/select signal.
How do you calculate multiplexers?
In general, to implement B : 1 MUX using A : 1 MUX , one formula is used to implement the same. KN-1 / A = KN = 1 (till we obtain 1 count of MUX). And then add all the numbers of MUXes = K1 + K2 + K3 + …. + KN.
What is the final output of multiplexer?
Multiplexer is a combinational circuit that has maximum of 2n data inputs, ‘n’ selection lines and single output line. One of these data inputs will be connected to the output based on the values of selection lines.
How many select lines are required for a 1 to 64 demultiplexer?
Therefore, for 1:4 demultiplexer, 2 select lines are required. Explanation: A demultiplexer sends a single input to multiple outputs, depending on the select lines.
Is multiplexer an encoder?
The digital circuits that perform encoding of digital information are called encoders while digital circuits that decode the coded digital information are called decoders. An encoder with enable pins is called multiplexer while a decoder with enable pins is called demultiplexer.
How to implement an 8 : 1 line multiplexer using two 4-1 lines?
Take two 4:1 mux and connect their ooutput to a 2:1 mux inputs. The result is a 8:1 mux. Now you will be having 8 input lines, 1 output line and 3 control lines.
How many inputs does a 4 by 1 multiplexer need?
The output will depend upon the combination of S2,S1 & S0 as shown in the truth table. Now, to implement this 8X1 MUX using 4X1 MUX we need two 4X1 MUX, since to take 8 inputs atleast two 4X1 MUX required, 4 inputs on each of the muxes having selection lines S1 & S0 as shown in the figure.
Which is the best example of a 2n × 1 multiplexer?
This type of multiplexer is referred to as 2n × 1 multiplexer or 2n -to-1 multiplexer. For example, if one of the 4 input lines has to be selected, then two select lines are required. Similarly, to select one of 8 input lines, three select lines are required.
Which is the operation of 8 : 1 MUX?
The operation of 8:1 MUX is described in the truth table. The expression for the data output can be derived from the truth table This can be implemented using eight 4-input AND gates, an 8-input OR gate, and three inverters. Higher-Order MUX Using Lower Order MUX
How do you make an 8-to-1 multiplexer? An 8-to-1 multiplexer consists of eight data inputs D0 through D7, three input select lines S0 through S2 and a single output line Y. Depending on the select lines combinations, multiplexer selects the inputs. How many select lines are there in a 8-to-1 multiplexer? 3 selection lines The…